(y+2)(2y^2-2y-3)=

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Solution for (y+2)(2y^2-2y-3)= equation:


Simplifying
(y + 2)(2y2 + -2y + -3) = 0

Reorder the terms:
(2 + y)(2y2 + -2y + -3) = 0

Reorder the terms:
(2 + y)(-3 + -2y + 2y2) = 0

Multiply (2 + y) * (-3 + -2y + 2y2)
(2(-3 + -2y + 2y2) + y(-3 + -2y + 2y2)) = 0
((-3 * 2 + -2y * 2 + 2y2 * 2) + y(-3 + -2y + 2y2)) = 0
((-6 + -4y + 4y2) + y(-3 + -2y + 2y2)) = 0
(-6 + -4y + 4y2 + (-3 * y + -2y * y + 2y2 * y)) = 0
(-6 + -4y + 4y2 + (-3y + -2y2 + 2y3)) = 0

Reorder the terms:
(-6 + -4y + -3y + 4y2 + -2y2 + 2y3) = 0

Combine like terms: -4y + -3y = -7y
(-6 + -7y + 4y2 + -2y2 + 2y3) = 0

Combine like terms: 4y2 + -2y2 = 2y2
(-6 + -7y + 2y2 + 2y3) = 0

Solving
-6 + -7y + 2y2 + 2y3 = 0

Solving for variable 'y'.

The solution to this equation could not be determined.

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